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Circle Problem
Picture a circle that only touches two sides of a square around it. The distance between the edge of the circle and the sides of the square are equal. The square is obviously equal on all sides and the circle is a normal circle.Now in algebra terms how would you figure out the area outside the circle?
Now in real numbers what is the area if the squares length and width is 16 and the distance between the edges of the circle that miss the square edges is 2?
For those good ones out there will understand this problem .
asked in maths



mido_chessmachine answers:

hey man you are setting traps here or what this is impossible mathematically why? actually iam emparsed to explain this mathematical fact that a child without any mathematical preparation can figure out .. grow up man .


Supplement from 12/07/2008 09:47pm:

if you said to me that you are talking in 3d space then the area is infinity which is also abavios


Supplement from 12/07/2008 10:08pm:

hey zak there is nothing personal but i just dont like undervaluation other people out there


Supplement from 12/07/2008 11:04pm:

and the only case is bretty easy


Supplement from 12/07/2008 11:05pm:

which sias explained down there


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Messerwisser answers:

As the circle is touching the perfect square on only two sides this must be a three-dimensional problem. There is no limit in how many positions this can give.
The area of a space is something only you can figure out.
Good luck!


Supplement from 12/07/2008 11:14pm:

Got me!


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siasl74 answers:

The circle is in a corner of the square, you didn't say that the sides it was touching were opposite (which would be impossible in 2-d).

If the quare has side length 16, it has area 256. If the circle doesn't touch 2 sides by 2, then its diameter must be 14, ie. the radius is 7. Therefore, the area of the circle is around 150, leaving an area outside the circle of around 156


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RFMJR answers:

I have arrived at the same interpretation as sias174 of the problem you stated,namely, that the circle sits in a corner of a square. the area of the square is 16 x 16 or 256.
The area of the circle is 22/7 x 7x7 or 154.
the area outside the circle but within the square is therefore 256 less 154 or 102.
By the way, 22/7 is the value of pi, and the area of any circle is pi times the square of the radius...ok, pi is 3.14159.....if you want to be picky!


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Armcie answers:

We have a circle inside a square.

In basic terms, the area outside the circle is simply the area of the square minus the area of the circle.

If we are given the length of one of the sides of the square (s) and the distance between the edge of the circle and the square (d) then:
we know the diameter of the circle is s-d and so the radius is (s-d)/2

Then area of the square = s^2
area of circle = pi x ((s-d)/2)^2
And the area outside the circle is:
s^2 - (pi x ((s-d)/2)^2)

In practical terms, with s = 16 and d = 2, then we can plug these numbers in to get:
256 - pi x 49
= 102.061


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